拖动(Draggable) - 还原位置
当带有布尔值 revert
选项的 draggable 停止拖拽时,返回 draggable(或它的助手)到原始位置。
源代码
<!doctype html> <html lang="en"> <head> <meta charset="utf-8"> <title>jQuery UI 拖动(Draggable) - 还原位置</title> <link rel="stylesheet" href="//code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css"> <script src="//code.jquery.com/jquery-1.9.1.js"></script> <script src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script> <link rel="stylesheet" href="http://jqueryui.com/resources/demos/style.css"> <style> #draggable, #draggable2 { width: 100px; height: 100px; padding: 0.5em; float: left; margin: 0 10px 10px 0; } </style> <script> $(function() { $( "#draggable" ).draggable({ revert: true }); $( "#draggable2" ).draggable({ revert: true, helper: "clone" }); }); </script> </head> <body> <div id="draggable" class="ui-widget-content"> <p>还原</p> </div> <div id="draggable2" class="ui-widget-content"> <p>还原助手</p> </div> </body> </html>