如何绑定一个滑块到一个已有的 select 元素。选择保持可见以便显示变化。当选择改变时,同时更新滑块。

<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>jQuery UI 滑块(Slider) - 绑定到 select 的滑块</title>
  <link rel="stylesheet" href="//code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css">
  <script src="//code.jquery.com/jquery-1.9.1.js"></script>
  <script src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
  <link rel="stylesheet" href="http://jqueryui.com/resources/demos/style.css">
  <script>
  $(function() {
    var select = $( "#minbeds" );
    var slider = $( "<div id='slider'></div>" ).insertAfter( select ).slider({
      min: 1,
      max: 6,
      range: "min",
      value: select[ 0 ].selectedIndex + 1,
      slide: function( event, ui ) {
        select[ 0 ].selectedIndex = ui.value - 1;
      }
    });
    $( "#minbeds" ).change(function() {
      slider.slider( "value", this.selectedIndex + 1 );
    });
  });
  </script>
</head>
<body>
 
<form id="reservation">
  <label for="minbeds">最小的床位数</label>
  <select name="minbeds" id="minbeds">
    <option>1</option>
    <option>2</option>
    <option>3</option>
    <option>4</option>
    <option>5</option>
    <option>6</option>
  </select>
</form>
 
 
</body>
</html>